Is #f(x) =e^x-x^3-3x# concave or convex at #x=0#?
1 Answer
Aug 23, 2017
Concave
Explanation:
Compute the second derivative.
#f'(x) = e^x - 3x^2 - 3#
#f''(x) = e^x - 6x#
At
#f''(0) = e^0 - 6(0) = 1#
Since this value is positive, the function is concave at
Hopefully this helps!