# Is it possible to factor y=2x^2+2x-2 ? If so, what are the factors?

Apr 19, 2018

Yes. See below

#### Explanation:

$2 {x}^{2} + 2 x - 2 = 2 \left({x}^{2} + x - 1\right) =$

$x = \frac{- 1 \pm \sqrt{1 + 4}}{2} = \frac{- 1 \pm \sqrt{5}}{2} \ddots$
$2 {x}^{2} + 2 x - 2 = 2 \left({x}^{2} + x - 1\right) =$
$= 2 \left(x - \frac{- 1 - \sqrt{5}}{2}\right) \left(x - \frac{- 1 + \sqrt{5}}{2}\right)$