# Is it possible to factor #y=2x^2 -452x-68#? If so, what are the factors?

##### 1 Answer

Jun 29, 2016

#### Explanation:

**Step 1: Removing the obvious integer common factor:**

From this point on there are no "pretty" factors but...

**Step 2: Use the quadratic formula to find the roots**

For the general quadratic:

#ax^2+bx+c# the roots are given by:

#color(white)("XXX")x=(-b+-sqrt(b^2-4ac))/(2a)# In this case

#color(white)("XXX")x=(226+-sqrt((-226)^2-4(1)(-35)))/(2(1))#

So we can continue the factoring as: