Is it possible to factor #y=2x^3-2x^2+2x-2 #? If so, what are the factors?

2 Answers
Apr 4, 2018

Answer:

Yes, it is possible to factor this. Here is what I did:

Explanation:

#y = 2x^3-2x^2+2x-2#

#y = 2x^2(x-1) + 2(x-1)#

#y = (2x^2+2)(x-1)#

The factors are #(2x^2+2)# and #(x-1)#.

Apr 4, 2018

Answer:

#y=2(x^2+1)(x-1)#

Explanation:

#y=2x^3-2x^2+2x-2#
Greatest common factor:
#y=2*(x^3-x^2+x-1)#
Factor by grouping:
#y=2*((x^3-x^2)+(x-1))#
#y=2*(x^2*(x-1)+1*(x-1))#
#y=2*(x^2+1)*(x-1)#
Thus, the factors are #2#, #(x^2+1)#, and #(x-1)#
graph{2x^3-2x^2+2x-2 [-10, 10, -5, 5]}