Is it possible to factor #y= 35x^2 - 22x + 3 #? If so, what are the factors?

1 Answer
George C.
May 10, 2016

#y=35x^2-22x+3=(5x-1)(7x-3)#

Explanation:

Use an AC method:

Find a pair of factors of #AC=35*3 = 105# with sum #B=22#.

The pair #15, 7# works in that #15*7 = 105# and #15+7=22#

Use this pair to split the middle term and factor by grouping:

#35x^2-22x+3#

#=35x^2-15x-7x+3#

#=(35x^2-15x)-(7x-3)#

#=5x(7x-3)-1(7x-3)#

#=(5x-1)(7x-3)#

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