Is it possible to factor #y=3x^2-11x+6#? If so, what are the factors?

1 Answer
Jun 12, 2018

Answer:

#(x-3)(3x-2)#

Explanation:

#"using the a-c method to factor the quadratic"#

#"the factors of the product "3xx6=18#

#"which sum to " - 11" are " - 9 " and " - 2#

#"split the middle term using these factors"#

#3x^2-9x-2x+6larrcolor(blue)"factor by grouping"#

#=color(red)(3x)(x-3)color(red)(-2)(x-3)#

#"take out the "color(blue)"common factor "(x-3)#

#=(x-3)(color(red)(3x-2))#

#3x^2-11x+6=(x-3)(3x-2)#