# Is it possible to factor y=x^2 + 3x - 28 ? If so, what are the factors?

Dec 23, 2015

Yes. $y = \left(x - 4\right) \left(x + 7\right)$
$y = a {x}^{2} + b x + c$
In this case $a = 1$, $b = 3$ and $c = - 28$
$y = \left(x - 4\right) \left(x + 7\right)$