# Is it possible to factor y=x^2-8x+3 ? If so, what are the factors?

Mar 11, 2018

Yes, it is possible. The factors are $\left(4 + \sqrt{13}\right)$ and $\left(4 - \sqrt{13}\right)$.

#### Explanation:

$y = {x}^{2} - 8 x + 3$

$x = \frac{- \left(- 8\right) \pm \sqrt{{\left(- 8\right)}^{2} - 4 \left(1\right) \left(3\right)}}{2 \left(1\right)}$
$\textcolor{w h i t e}{x} = \frac{8 \pm \sqrt{52}}{2}$
$\textcolor{w h i t e}{x} = \frac{8 \pm 2 \sqrt{13}}{2}$
$\textcolor{w h i t e}{x} = 4 \pm \sqrt{13}$
$y = \left(4 + \sqrt{13}\right) \left(4 - \sqrt{13}\right)$