# Is it possible to factor y=x^4 + 27x ? If so, what are the factors?

Jun 28, 2016

Yes $y = {x}^{4} + 27 x = x \left(x + 3\right) \left({x}^{2} - 3 x + 9\right)$

#### Explanation:

$y = {x}^{4} + 27 x$

= $x \left({x}^{3} + 27\right)$

= $x \left({x}^{3} + 3 {x}^{2} - 3 {x}^{2} - 9 x + 9 x + 27\right)$

= $x \left({x}^{2} \left(x + 3\right) - 3 x \left(x + 3\right) + 9 \left(x + 3\right)\right)$

= $x \left(x + 3\right) \left({x}^{2} - 3 x + 9\right)$