The probability that the first card is a face card out of 52 cards is $\frac{3 \cdot 4}{52} = \frac{12}{52} = \frac{3}{13}$ (there are three face cards J, Q, and K for each of the four suits). The probability that the second card is an ace out of the 51 remaining cards is $\frac{4}{51}$ (there are four aces in the 51 remaining cards since the first card is not an ace).
Multiplying these two gives $\frac{3}{13} \cdot \frac{4}{51} = \frac{4}{221}$.