Is the function #f(x)=x^2/(x-1)# even, odd or neither?
It is neither odd or even.
First of all if you want to discuss if a function is odd or even, the domain of the function must be symetrical to 0 (in other words if
Function given in this task does not satisfy this condition, because
# = x^2/(-x-1) = x^2/-(x+1) = -x^2/(x+1)#