Is the function #y=x^4# odd, even, or neither?

2 Answers
Dec 9, 2017

It is even. See explanation.

Explanation:

To check if a function is even, odd or neither you have to calculate #f(-x)# and compare the result with the original function:

  • if #f(-x)=f(x)# then the function is even,

  • if #f(-x)=-f(x)# then the function is odd,

  • in other cases the function is neither odd or even.

Here we have:

#f(x)=x^4#

#f(-x)=(-x)^4=x^4#

#f(-x)=f(x)#, so the function is even.

Note:

Generally the function #y=x^n# is odd for odd values of the exponent and even for even exponent.

Other way of checking if the function is odd or even is to look at its graph:

The #Y# axis is the axis of symetry of an even function. The example can be:

graph{x^2 [-10, 10, -5, 5]}

If a function is even then the origin is its center of symetry:

graph{x^5 [-10,10,-5,5]}

Dec 9, 2017

#y=x^4" is even"#

Explanation:

#"to determine if y is odd/even"#

#• " if "f(x)=f(-x)" then "f(x)" is even"#

#"even functions are symmetrical about the y-axis"#

#• " if "f(-x)=-f(x)" then "f(x)" is odd"#

#"odd functions have half turn symmetry about the origin"#

#f(-x)=(-x)^4=x^4=f(x)#

#rArry=x^4" is even"#
graph{x^4 [-10, 10, -5, 5]}