Is the function #y=x^5+7x^3# even or odd?

1 Answer
Nov 10, 2016

#y=x^5+7x^3# is an odd function.

Explanation:

A function is odd if #f(-x)=-f(x)# and is even if #f(-x)=f(x)#.

As function is #y=f(x)=x^5+7x^3#

and #f(-x)=(-x)^5+7(-x)^3=-x^5-7x^3=-f(x)#

Hence #y=x^5+7x^3# is an odd function.