Is the sequence "#4, 16, 36, 64,...#" arithmetic?

1 Answer
Nov 10, 2015

No, it has no common difference between successive terms.

The terms are given by the formula #a_n = 4 n^2# where #n = 1,2,3,...#

Explanation:

Write out the original sequence:

#color(blue)(4), 16, 36, 64#

Write out the sequence of differences of the sequence:

#color(blue)(12), 20, 28#

Since this is not constant, the sequence is not arithmetic.

Write out the sequence of differences of that sequence:

#color(blue)(8), 8#

This is a constant sequence, so we can derive a polynomial formula for the terms of the sequence from the initial term of each of these sequences:

#a_n = color(blue)(4)/(0!) + color(blue)(12)/(1!)(n-1) + color(blue)(8)/(2!)(n-1)(n-2)#

#= 4+12n-12+4n^2-12n+8 = 4n^2#