# Is x^2(1/y)=3 a linear function?

Nov 5, 2016

No, ${x}^{2} \left(\frac{1}{y}\right) = 3$ is not a linear function.

#### Explanation:

To be linear, there are certain conditions which must be met.

1) No variable can have an exponent other than $+ 1$.
2) No variable can be in a denominator.
3) No variable can be inside absolute value lines.
4) No variable can be part of a radicand.
5) No term can have more than one variable.

The function ${x}^{2} \left(\frac{1}{y}\right) = 3$ violates both conditions 1 and 2. Therefore it is not a linear function.