Is #x^2(1/y)=3# a linear function?

1 Answer
Nov 5, 2016

No, #x^2(1/y) = 3# is not a linear function.


To be linear, there are certain conditions which must be met.

1) No variable can have an exponent other than #+1#.
2) No variable can be in a denominator.
3) No variable can be inside absolute value lines.
4) No variable can be part of a radicand.
5) No term can have more than one variable.

The function #x^2(1/y) = 3# violates both conditions 1 and 2. Therefore it is not a linear function.