# It takes 3,190 J to increase the temperature of a 0.400 kg sample of glass from 273 K to 308 K. What is the specific heat for this type of glass?

##### 1 Answer

May 29, 2018

#### Explanation:

Specific heat is given by

#"S" = "Q"/"mΔT"#

Where

#"Q ="# Heat added/liberated#"m ="# Mass of sample#"ΔT ="# Change in temperature