# It took 7 min to move a refrigerator. You did 350 J of work in the process. How much power was required to move the refrigerator?

Jun 10, 2017

$\frac{5}{6}$ $\text{W}$ is the answer.

#### Explanation:

$\text{1 minute = 60 s}$

$\text{7 minutes = 420 s}$

Now,

$E = P \times t$

so

$P = \frac{E}{t}$

$P = \text{350 J"/"420 s}$

$P = \frac{5}{6}$ $\text{W}$