# Jocelyn has $1.95 in her pocket made up of 27 nickels and dimes. How many of each type of coin does she have? ##### 1 Answer Nov 21, 2016 Jocelyn has 15 nickels and 12 dimes in her pocket. #### Explanation: First, let's call the number of dimes Jocelyn has $d$and the number of nickels she has $n$. We then know the number of dimes and the number of nickels are 27 or $d + n = 27$We can solve this for $d$: $d + n - n = 27 - n$$d = 27 - n$Next we know a dime is worth $0.10 and a nickel is worth $0.05 and we know she has a total of $1.95 in her pocket so we can write:

$0.10d +$0.05n = $1.95 From the first equation we can substitute $27 - n$for $d$in the second equation and solve for $n$; $0.10(27 - n) + $0.05n =$1.95

($0.10*27) -$0.10n + $0.05n =$1.95

$2.70 -$0.05n = $1.95 $2.70 - $2.70 -$0.05n = $1.95 -$2.70

-$0.05n = -$0.75

(-$0.05n)/(-$0.05) = (-$0.75)/(-$0.05)

$n = 15$

Now that we know there are 15 nickels ($n = 15$) we can substitute $15$ for $n$ in the solution for the first equation and calculate the number of dimes or $d$:

$d = 27 - 15$

$d = 12$