# KClO3 → KCl + O2 How many grams of oxygen are produced in the decomposition of 5.00 grams of potassium chlorate?

May 1, 2018

$\text{1.96g}$ ${O}_{2}$

#### Explanation:

We first need our balanced equation:
$2 K C l {O}_{3} \rightarrow 2 K C l + 3 {O}_{2}$

Now apply stoichiometry, and you result with this:

$5.00 \text{g 2KClO3" * "1mol 2KClO3"/"122.55g 2KClO3" * "3mol O2"/"2mol 2KClO3" * "16.00g O2"/"1mol O2" = "1.96g O2}$