Let #"*"# defined in #ZZ# by #p"*"q=p+q+3# for all #p,q in ZZ# Show that a) #"*"# is commutative in #ZZ#. b) identity element w.r.t #"*"# exists in #ZZ#?
1 Answer
Apr 20, 2017
See explanation...
Explanation:
a)
For all
#p "*" q = p+q+3 = q+p+3 = q "*" p#
So
b)
#p "*" (-3) = p+(-3)+3 = p#
#(-3) "*" p = (-3)+p+3 = p#
So