Let #f(x) = 2x-1#, #g(x) = 3x#, and #h(x) = x^2 + 1#. Compute the following ?

Question

#f(x+1)#

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Answer 1 · 2018-02-06T10:57:23

#f(x+1)= 2x+1#

To compute #f(x+1)#, start with #f(x)#:

#f(x)= 2x-1#

Substitute #x+1# for every x:

#f(x+1)= 2(x+1)-1#

Simplify:

#f(x+1)= 2x+2-1#

#f(x+1)= 2x+1#