Let #f(x,y)={(x²y)/(x⁴+y²), " if " x⁴+y²≠0, {0, " if " x=y=0#. Check whether #lim_((x,y)→(0,0))f(x,y) # exists or not?

1 Answer
Feb 17, 2018

See below.

Explanation:

Choosing a line such that #y = lambda x# we have

#lim_((x,y)->(0,0))f(x,y) = lim_(x->0)(x^3lambda)/(lambda^2 x^2 + x^4) = lim_(x->0)(xlambda)/(lambda^2 + x^2)=0#

but now choosing a curve such that #y = x^2# we have

#lim_((x,y)->(0,0))f(x,y) = lim_(x->0)x^4/(x^4+x^4) = 1/2# then

#lim_((x,y)->(0,0))f(x,y) # does not exists.