# Let x > 0, prove x^2 + 1 > lnx?

##### 2 Answers

Two cases:

For

For

For all

We've shown both cases, so this is true for all

As

#### Explanation:

For any number

As

Graphically it is quite clear:

Jun 22, 2018

Two cases:

For

For

For all

We've shown both cases, so this is true for all

Jun 22, 2018

As

For any number

As

Graphically it is quite clear: