#B_1={i=(1,0,0),j=(0,1,0),k=(0,0,1)}# is a Basis for
#x=(x_1,x_2,x_3)=x_1i+x_2j+x_3k#.
Also, #B_2={baru=(1,0,0),barv=(0,1,2),barw=(0,2,1)}# serves as
the Basis for #y=(y_1,y_2,y_3)#, so that,
#y=(y_1,y_2,y_3)=y_1baru+y_2barv+y_3barw#.
But,
#baru=(1,0,0)=1i+0j+0k#,
#barv=(0,1,2)=0i+1j+2k, and #
#barw=(0,2,1)=0i+2j+1k#.
#:. y=(y_1,y_2,y_3)=y_1baru+y_2barv+y_3barw#,
#=y_1(1i+0j+0k)+y_2(0i+1j+2k)+y_3(0i+2j+1k)#,
#=(y_1i)+(y_2j+2y_2k)+(2y_3j+y_3k)#,
#=y_1i+(y_2+2y_3)j+(2y_2+y_3)k#.
Knowing that, #Q(x)=Q(x_1,x_2,x_3)=Q(x_1i+x_2j+x_3k)#,
#=x_1^2+2x_1x_2+2x_2x_3+x_2^2+x_3^2#,
#=x_1^2+x_2^2+x_3^2+2x_1x_2+2x_2x_3color(red)(+2x_3x_1-2x_3x_1)#
#:. Q(x_1i+x_2j+x_3k)=(x_1+x_2+x_3)^2-2x_3x_1#.
Accordingly, #Q(y)=Q(y_1i+(y_2+2y_3)j+(2y_2+y_3)k)#,
#={y_1+(y_2+2y_3)+(2y_2+y_3)}^2-2(2y_2+y_3)y_1#,
#=(y_1+3y_2+3y_3)^2-2(2y_2+y_3)y_1#,
#=(y_1^2+9y_2^2+9y_3^2+6y_1y_2+18y_2y_3+6y_3y_1)-4y_1y_2-2y_3y_1#,
#rArr Q(y_1,y_2,y_3)=y_1^2+9y_2^2+9y_3^2+2y_1y_2+18y_2y_3+4y_3y_1#,
is the desired expression!
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