Lim to infinity of (5x^2-3x+4)/(x-1)^2?

show working out pls

1 Answer
Jim G.
Nov 13, 2017

#5#

Explanation:

#"divide terms on numerator/denominator by the highest"#
#"power of x that is "x^2#

#rArr(5x^2-3x+4)/(x^2-2x+1)#

#=((5x^2)/x^2-(3x)/x^2+4/x^2)/(x^2/x^2-(2x)/x^2+1/x^2)=(5-3/x+4/x^2)/(1-2/x+1/x^2)#

#rArrlim_(xtooo)(5x^2-3x+4)/(x-1)^2#

#=lim_(xtooo)(5-3/x+4/x^2)/(1-2/x+1/x^2)=5/1=5#

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