#lim_(x->3) (sqrt3x-3)/(sqrt(2x-4) - sqrt2)# Evalute?

1 Answer
Ratnaker Mehta
Apr 11, 2017

The Limit does not exist.

Explanation:

Reqd Lim.#=lim_(x to 3)(sqrt3x-3)/(sqrt(2x-4)-sqrt2).#

#=lim_(x to 3)(sqrt3x-3)/(sqrt(2x-4)-sqrt2)xx(sqrt(2x-4)+sqrt2)/(sqrt(2x-4)+sqrt2).#

#=lim_(x to 3) {(sqrt3x-3)(sqrt(2x-4)+sqrt2)}/{(2x-4)-2}#

#=lim_(x to 3){(sqrt3x-3)(sqrt(2x-4)+sqrt2)}/{2(x-3)}#

So, as long as, #(x-3)# is there in the Dr., the limit does not exist.

Related questions
See all questions in Determining Limits Algebraically
Impact of this question
1741 views around the world
You can reuse this answer
Creative Commons License