Question

`lim_(x->oo)((sqrt(x)/(|__x__|))`?

Answer 1

Zero

Explanation:

=`lim_(xrarroo) ((sqrtx/absx)`

=`lim_(xrarroo) ((sqrtx/(sqrtx sqrtx))`

=`lim_(xrarroo) (1/sqrtx)`

Applying limit

=`1/sqrtoo`

Anything divide by infinity is equal to zero

=`0`

Hope this helps!