# Lnx-ln5=10?

##### 1 Answer

Feb 13, 2018

#### Explanation:

We have:

# ln x -ln 5 = ln 10 #

Using the result lnA=lnB=ln(A/B)# we can write:

# ln(x/5) = ln10 #

The logarithm is a

# ln A= ln B iff A=B #

And so we have:

# x/5 = 10 => x =50#