What is #log_5 10 - log_5 2# ?
1 Answer
May 17, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)logx-logy=log(x/y)#
#•color(white)(x)log_b b=1#
#rArrlog_5 10-log_5 2=log_5(10/2)=log_5 5=1#
