Log2(x+1)=log4(x^2-x+4) What is the value of x?
Lets start by converting the
So we can rewrite our expression as
Multiply both sides of this equation by 2.
Now we can use the property of logarithms that says
If the logs are equal, then their arguments must be equal.
Expand the squared binomial on the left-hand side of this equation.
Combine like terms.
Divide both sides by 3.
Check to make sure this makes sense by plugging this value for