Magnetic field?

1.) An atomic particle of charge +1.6×10−19C, travels at a speed of 3.0×106m s-1, in a plane perpedicular to a magnetic field 0.50T. If the radius of motion of the particle 6.27×10−2m, what is the mass of the particle ?
Give your answer in kg.

2.) Can you guess what kind of particle this is?
a.) Proton
b.) Neutron
c.) Electron

1 Answer
Mar 25, 2018

#1.67 times 10^(-27)# Kg

From the mass, this should be a proton. (In any case, the charge was given as positive - so neither electrons nor neutrons fit the bill)

Explanation:

The magnetic force here provides the centripetal force required for the circular orbit. Si

#(mv^2)/r =qvB#

We can rewrite this to fond the mass:

# m = (qBr)/v = (1.6times 10^(-19) times 0.5 times 6.27times 10^(-2))/(3 times 10^6) " Kg" ~~ 1.67times 10^(-27)" Kg"#