# Make 30.0 mL of H2 gas from the reaction of 6M HCL and Aluminum. How do I do the Stoichiometry for this problem?

## I think the chemical equation is: 3HCl + Al -----> Al(Cl)3 + H3

The chemical equation is $6 H C l + 2 A l \to 2 A l C {l}_{3} + 3 {H}_{2}$.
30 mL of ${H}_{2}$ correspond to 1.34 millimoles .According to stoichiometric ratio, 3 moles of ${H}_{2}$ come from 2 moles of $A l$, therefore 1.34 mmoles come from 0.89 mmoles of Aluminium, =24.1 milligrams