Mass of a body is 500g . It is thrown vertically upward with kinetic energy 58.8j . So its kinetic energy reduce to half at which height?

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Gaya3 Share
Oct 21, 2017

Answer:

#6"m"#

Explanation:

Initial Kinetic Energy #="KE"_i=58.8J#

Final Kinetic Energy #="KE"_f=58.8/2=29.4J#

Let's assume that the rest of Kinetic Energy has been converted into Gravitational potential energy.

Initial Gravitational potential Energy #="PE"_i=0J#

Final Gravitational potential Energy #="PE"_f=58.8-29.4=29.4J#

We need to know the height #color(blue)h#

So, #"PE"_f=mgcolor(blue)h#

#=>29.4J=0.5"kg"xx9.8m/s^2xxcolor(blue)h#

#=>color(blue)h=(29.4J)/(0.5"kg"xx9.8m/s^2)#

#=>color(blue)h=(29.4cancelN m)/(0.5cancel"kg"xx9.8cancel(m/s^2))#

#color(blue)h=6m#

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Oct 21, 2017

Answer:

6m

Explanation:

When the Kinetic energy has reduced to half, the other part has become gravitational potential energy #E_w=mgh=(58,8 J)/2= 29,4 J#
hence #h=E_w/(mg) = (29,4J)/(0,5kg xx 9,8m/s^2)=6m#

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