Question

Math: trig problem involving identities?

sec^2 x - 1 / sec ^ 2 x = sin ^2 x

Answer 1

`=sin^2 x`

Explanation:

`=(sec^2x-1)/sec^2x`

`=(sec^2x)/sec^2x - (1)/sec^2x`

`=1-cos^2x`

`=sin^2x`