Meghan has 900 pieces of candy. If #C(t)# represents the number of pieces of candy remaining after #t# days, and Meghan eats 5 pieces of candy per day, how many pieces would she have left after 100 days?

2 Answers
Jan 31, 2018

400.

Explanation:

Meghan eats 5 pieces a day.

So, she will eat #5 * 100 = 500# pieces of candies in #100# days.

Total number of candies she had previously was #900#.

So, the remaining number of candies is #900 - 500 = 400#.

We can do this algebricaly too.

#C(t)# represents the remaining number of pieces of candies after #t# days.

So, #C(t) = 900 - 100t#

Now, plug the value of #t# in the function #C(t)#,

#C(t) = 900 - 100 * 5 = 900 - 500 = 400#

Hope this helps.

Jan 31, 2018

Meghan would have left with # 400# pieces of candy after #100# days.

Explanation:

Total number of pieces of candy is #X=900# Meghan eats #d=5#

pices of candy per day and #C(t)# represents number of pieces

of candy left after #t# days , then #C(t)=X-d*t#

#:. C(t)= 900 - 5*t ; t=100#

# :. C(100)= 900 - 5*100 =400#

Meghan would have left with #400# pieces of candy after #100#

days. [Ans]