# Michael shot 50 free throws as practice before the championship game since it is known that free throw percentage can really determine the outcome of a basketball game. he missed 6 free throws?

## what percentage of the attempted free throws did Michael make?

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#### Explanation

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#### Explanation:

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Feb 8, 2018

See a solution process below:

#### Explanation:

If Michael missed 6 oout of 50 free throws then he made:

$50 - 6 = 44$

Let's call $p$ the percentage of free throws Michael made.

"Percent" or "%" means "out of 100" or "per 100",

Therefore p% can be written as $\frac{p}{100}$.

Because Micheal made 44 out of 50 free throws we can write an equation to find $p$ as:

$\frac{p}{100} = \frac{44}{50}$

$\textcolor{red}{100} \times \frac{p}{100} = \textcolor{red}{100} \times \frac{44}{50}$

$\cancel{\textcolor{red}{100}} \times \frac{p}{\textcolor{red}{\cancel{\textcolor{b l a c k}{100}}}} = \cancel{\textcolor{red}{100}} \textcolor{red}{2} \times \frac{44}{\textcolor{red}{\cancel{\textcolor{b l a c k}{50}}}}$

$p = \textcolor{red}{2} \times 44$

$p = 88$

Michael made $\frac{88}{100}$ or 88% of the practice free throws.

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