# NaOH + KMnO4: why doesn't it yield NaMnO4+KOH?

## I've learned that the reaction goes like this: $2 N a O H + K M n {O}_{4} \to 2 K O H + 2 N {a}_{2} O + M n {O}_{2}$ But why doesn't it yield NaMnO4 and KOH instead?

The reaction you have written above features a reduction ($M n \left(V I I\right) \to M n \left(I V\right)$, but no corresponding oxidation. Would you review your source?