On what interval is the object's velocity positive? Negative?

An object is shot upwards and its height (in feet) from the ground after t seconds is given by #h(t)=-16t^2+128t+144#

On what interval is the object's velocity positive? Negative?

1 Answer
Nov 9, 2017

velocity is positive if #t lt 4#
velocity is negative if #t gt 4#

Explanation:

The height of the object is:

# h(t) = -16t^2+128t+144#

The velocity is given by the first derivative, so differentiating wrt #t# we have:

# h'(t) = -32t+128#

Let us consider the values of #t# for which # h'(t) = 0#:

# h'(t) = 0 => -32t+128 =0#
# :. 32t=128 #
# :. t = 4 #

And so:

  • velocity is positive if #t lt 4#
  • velocity is negative if #t gt 4#