# One day the temperature started at -6°F and dropped 16° by the end of the day. What was the temperature at the end of the day?

Mar 4, 2018

See a solution process below:

#### Explanation:

Saying the temperature dropped ${16}^{o}$ means it went down by ${16}^{o}$.

Therefore we need to subtract ${16}^{o}$ from the starting point which was $- {6}^{o}$.

$- {6}^{o} - {16}^{o} = - {22}^{o}$

The temperature at the end of the day was a cold $- {22}^{o}$

Mar 4, 2018

-22°F

#### Explanation:

The temperature starts off at -6°F.

By the end of the day, it dropped by 16°F. This means you have to add the dropped temperature to find the 'end of the day' temperature. By dropping 16°F, we can say that we have to add -16°F to the original temperature.

So,

-6°F + (-16°F) = -22°F