One integer is 15 more than 3/4 of another integer. The sum of the integers is greater than 49. How do you find the least values for these two integers?

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Answer 1 · 2018-06-11T11:51:59

The 2 integers are 20 and 30.

Let x be an integer
Then #3/4x+15# is the second integer

Since the sum of the integers is greater than 49,
#x+3/4x+15 >49#

#x+3/4x >49-15#

#7/4x > 34#

#x > 34times4/7#

#x > 19 3/7#

Therefore, the smallest integer is #20# and the second integer is #20times3/4+15 = 15+15= 30#.