# One integer is 15 more than 3/4 of another integer. The sum of the integers is greater than 49. How do you find the least values for these two integers?

Jun 11, 2018

The 2 integers are 20 and 30.

#### Explanation:

Let x be an integer
Then $\frac{3}{4} x + 15$ is the second integer

Since the sum of the integers is greater than 49,
$x + \frac{3}{4} x + 15 > 49$

$x + \frac{3}{4} x > 49 - 15$

$\frac{7}{4} x > 34$

$x > 34 \times \frac{4}{7}$

$x > 19 \frac{3}{7}$

Therefore, the smallest integer is $20$ and the second integer is $20 \times \frac{3}{4} + 15 = 15 + 15 = 30$.