# One leg of an isosceles right triangle is 10 inches, how do you find the perimeter of the right triangle?

Hypotenuse: c^2 = 100 + 100 = 200 --> $c = 10 \sqrt{2}$
Perimeter: $10 + 10 + 10 \sqrt{2} = 10 \left(2 + \sqrt{2}\right)$