One mole of non volatile solute is dissolved in two moles of water.The vapour pressure of the solution relative to that of water is?

1 Answer
Nov 12, 2017

#P_"soln" = X_"solv"*P_"solv"^0#

Given,

#P_(H_2O)^0 = 23.76"torr"#

#X_(H_2O) = (2"mol")/(3"mol") approx 2/3#.

Hence,

#P_"soln" = X_(H_2O)*P_(H_2O)^0 approx 15.8"torr"#

From here we may make a general observation that as the concentration of nonvolatile solute increase, vapor pressure decreases. Vapor pressure is a colligative property of solutions.