Question

Organic Chemistry Multiple Reagents Help?

Where do I even begin...

Answer 1

You have been given an order of operations....

Explanation:

Propionaldehyde is treated with ethyl magnesium bromide to give a secondary alkoxide...

`"H"_3"CCH"_2^(-)""^(+)"MgBr"+"H(O=)CCH"_2"CH"_3rarr"H"_3"CCH"_2(""^(-)"O"-")CHCH"_2"CH"_3`

And water work-up gives the alcohol....

`"H"_3"CCH"_2"CH(OH)CH"_2"CH"_3`

Now this is oxidized up to the ketone...`"3-pentanone"`

`"H"_3"CCH"_2"C(=O)CH"_2"CH"_3`

And this is treated with ethyl magnesium bromide to give the tertiary alcohoxide....and aqueous work-up gives the tertiraty alcohol...

`"H"_3"CCH"_2"C(OH)(CH"_3")CH"_2"CH"_3`

Grignard reagents are one of the few means of making `C-C` bonds....