# Oxidation of phenol with equation?

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#### Explanation

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#### Explanation:

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anor277 Share
Feb 8, 2018

Well, phenol is combustible....

#### Explanation:

${C}_{6} {H}_{5} O H \left(l\right) + 7 {O}_{2} \left(g\right) \rightarrow 6 C {O}_{2} \left(g\right) + 3 {H}_{2} O \left(l\right)$

Often when you burn this you see a black residue of carbon due to incomplete combustion. And if we wanted to represent SOME incomplete combustion we could include $C \left(s\right)$ and $C O \left(g\right)$ as products...

${C}_{6} {H}_{5} O H \left(l\right) + \frac{11}{2} {O}_{2} \left(g\right) \rightarrow 4 C {O}_{2} \left(g\right) + C O \left(g\right) + C \left(s\right) + 3 {H}_{2} O \left(l\right)$

Of course phenol could be selectively oxidized to quinones, but here we represent complete and incomplete combustion.

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