# Oxygen gas is collected in a 5.00-liter container at 25°C and 380 torr. How many moles of oxygen are present in the container?

Approx. $0.1 \cdot m o l$ ${O}_{2} \left(g\right)$
$n = \frac{P V}{R T}$ $=$ $\frac{\left(\frac{380}{760} \cdot a t m\right) \times 5.00 \cdot L}{0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1 \times 298 \cdot K}$ $=$ ?? $m o l$
Note that the answer is in moles of dioxygen, i.e. ${O}_{2}$ gas. Does the given answer have units of $m o l$? If it does not then somewhere I have made a mistake!
Note also that I used the conversion, $\text{760 mm Hg = 1 atmosphere}$.