# The pH of a 0.000001M solution of NaOH?

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This is a **very** dilute solution of **NaOH** so I would expect the pH to be 7 or very slightly above.

Because the concentration is so low we must also take into account the ions that are formed from the dissociation of water:

If you do a thought experiment you can imagine adding a small amount of NaOH to water such that its concentration =

The total concentration of

However this is **not** the concentration of

By adding those extra **disturbed** a system which is already at equilibrium. If you are familiar with Le Chatelier's Principle you will understand that such a system will react by opposing the change applied to it.

It will do this by shifting to the left thus reducing the concentration of

We need to set up an **ICE** table based on

Multiplying out this gives:

This is a quadratic equation which can be solved using the quadratic formula:

This gives:

Ignoring the absurd root gives:

From the ICE table we get:

As expected, very close to neutral.

This is why spillages of acid or alkali are irrigated with copious amounts of water to bring the pH towards neutrality.

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