We need to find the mass of one molecule of #"C"_6"H"_12"O"_6"#.
Mass of one molecule of #"C"_6"H"_12"O"_6"#
The mass of one molecule of #"C"_6"H"_12"O"_6"# is its molar mass #("180.156 g/mol")# divided by Avogadro's number, #6.022xx"10"^23##"molecules/mol"#.
Since #(6.022xx10^23"molecules")/("1 mol")# is a fraction, we can divide by multiplying by its reciprocal #("1 mol")/(6.022xx10^23"molecules")#
#"mass of one molecule"# #"C"_6"H"_12"O"_6"##=##(180.156"g C"_6"H"_12"O"_6)/(1color(red)cancel(color(black)("mol C"_6"H"_12"O"_6)))xx(1color(red)cancel(color(black)("mol C"_6"H"_12"O"_6)))/(6.022xx10^23"molecules")=2.989xx10^(-22)"g/molecule"#
Number of sugar molecules
To determine the number of molecules of #"C"_6"H"_12"O"_6"#, divide #1.15xx10^17"g C"# by #2.989xx10^(-22)" g/molecule"#. Since #"g"/"molecule"# is a fraction, we can divide by multiplying by its reciprocal #"molecule"/"g"#.
#1.15xx10^17color(red)cancel(color(black)("g C"))xx(1"molecule C"_6"H"_12"O"_6)/(2.989xx10^(-22)color(red)cancel(color(black)("g C")))=3.85xx10^38" molecules C"_6"H"_12"O"_6"#
Resource: https://www.chemteam.info/Mole/Mass-One-Molecule.html
