Given that in #DeltaABC,AB=AC#
#BX and CY # are bisectors of #/_ ABC and /_ ACB# respectively.
So # /_ ABC= /_ ACB#
#BY=4cm#, we are to find out length of #AX#
we have
#/_ ABC = /_ ACB #
#=>1/2/_ ABC = 1/2 /_ ACB #
#=>/_ ABX=/_ BCY#
( since #BX and CY # are bisectors of # /_ ABC and /_ ACB # respectively )
As we have #=>/_ ABX=/_ BCY#, the two circumferential equal angles of same circle, the length of the arcs on which these angles stand will be same .
Hence #arcBY=arcAX# and so chord#AX=#chord #BY=4cm#