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Feb 9, 2018

Answer:

#/_(BDC) = 64^0#

Explanation:

Given #AhatBC = AhatCB = 32^0# as #AB = AC#

Consider isosceles triangle ABC,

#BhatAC = 180 - (AhatBC + AhatCB) = 180 - 32 -32 = 116^0#

ABCD is a cyclic quadrilateral. Therefore #BhatAC + BhatDC = 180^0#

#BhatDC = 180 - BhatAC = 180 - 116 = 64^0#

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