Question

Please can anyone help me integrate sec^nx with step-by-step formular?

Answer 1

`d/dxsec^(n)x=nsec^n x tanx`

Explanation:

We will use two results for this question. Firstly, that

`d/dxsecx=secxtanx`.

And the chain rule

`d/dx [f(x)]^n=n[f(x)]^(n-1)f'(x)`

So

`d/dx sec^n x= nsec^(n-1)x(secxtanx)=nsec^nxtanx`